컴공생의 다이어리

[프로그래머스] 오랜 기간 보호한 동물(2) - MySQL SELECT I.ANIMAL_ID, I.NAME FROM ANIMAL_INS I, ANIMAL_OUTS O WHERE I.ANIMAL_ID = O.ANIMAL_ID ORDER BY O.DATETIME-I.DATETIME DESC LIMIT 2; # or SELECT I.ANIMAL_ID, I.NAME FROM ANIMAL_INS I INNER JOIN ANIMAL_OUTS O ON I.ANIMAL_ID = O.ANIMAL_ID ORDER BY O.DATETIME-I.DATETIME DESC LIMIT 2; # or # 'INNER' 생략 SELECT I.ANIMAL_ID, I.NAME FROM ANIMAL_INS I JOIN ANIMAL_OUTS..